60y^2+290y-50=0

Solution for 60y^2+290y-50=0 equation:

60y^2+290y-50=0

a = 60; b = 290; c = -50;
Δ = b2-4ac
Δ = 2902-4·60·(-50)
Δ = 96100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{96100}=310$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(290)-310}{2*60}=\frac{-600}{120}
=-5
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(290)+310}{2*60}=\frac{20}{120}
=1/6
$